Alan M Dunsmuir wrote:
> What your proof said was:
>> "I realised as I was taking a shower this morning that if x^n + y^n =
> z^n is true for some x, y and z, and n = 2, then it can't possibly also
> be true for any n > 2, since the left hand side will always be a little
> less than, or a little more than, the right hand side. QED"
Well, "P; therefore P" *is* valid. Of course, whether it is sound
is another matter ....
--
<J Q B>