Anshul wrote:
> Hi all,
>> I am working with papain and wanted to know about its extinction
> coefficient at 280 nm. I searched the internet and found it to be 25 but
> when I checked through the ProtParam tool of expassy it showed me the
> value as 56185.
>> Does anyone know what the exact value of extinction coefficient is for
> papain.
>> Regards,
> Ansh
>
I used to work with papain, and the value of 25 is correct. However, as
DK says, this is for a 10mg/ml solution, rather than the more normal
1mg/ml solution. A check of my thesis reminds me that this was
determined experimentally by Glaser & Smith in 1961 (J Biol Chem
236:2948-2951).
Geoff
