In article <92033.201318U50701 at uicvm.uic.edu> U50701 at uicvm.uic.edu (Yakof) writes:
>Hello there. I am taking introductory genetics this semester and one of the hom
>eworks asks to explain how 15:1 phenotypic ratio can be obtained from selfing
> F2; it is also specified that P1 were both pure lines. They are talking of mon
>ohybrid cross, by the way, but I do not see any possible way of getting 15:1 p
>henotypic ratio.
>Is anybody there willing to help out?
>Thanks a lot.
Oooops! I got carried away with my cleverness:
AABB x aabb => AaBb (X) => 15/16 A_B_ , 1/16 aabb
AAbb x aaBB => AaBb (X) => 15/16 A_B_, 1/16 aabb
IF these loci are independantly assorting and the game is dominant
epitasis. (It's early, folks, very early in the day.)
Anyway, I'm not sure the problem is well stated, or at least completely
stated. Can't think of a way to get 15:1 without at least two loci
involved.
Have a nice day, Yakof. :^)
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