John Fields <starship at freeside.fc.net> wrote in article
<5n6gft$on1$1 at yakuza.fc.net>...
> Arny Krüger (arnyk at pop3.concentric.net) wrote:
>>> : Luc.vanHoye at ping.be wrote in article <33935466.1CC at ping.be>...
> : > I am trying to figger out if the impedance of an audio device has
> : > something to do with how loud its signal can go...
>> : It does not.
>> : Impedance and sensitivity are separate specifications.
> It does.
>> Consider an amplifier with an 8 ohm output impedance feeding 8 volts into
> a speaker with an 8 ohm impedance. The speaker will be dissipating 8
> watts of power and will generate a specific sound pressure level.
>> Next, consider the same amplifier putting 8 volts into a 16 ohm load.
> Since P = E^2 / R, the power being pumped into the load is 8^2 / 16, or 4
> watts, which will yield a lower sound pressure level.
You're totally missing the point You are confusing voltage level with
You are putting LESS POWER into the 16 ohm speaker which results in a lower
sound level. This has absolutely nothing do do with efficiency which is
function of the physical engineering design of the speaker and the
>> The assumption, of course, is that both speakers have the same efficiency
> and are, in fact, identical except for their impedances.
If thet are of identical impedances, puting 1 watt of power into either
speaker will result the EXACT SAME sound level!
>> John Fields
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